X^2+8x=72

Solution for X^2+8x=72 equation:

X^2+8X=72

We move all terms to the left:

X^2+8X-(72)=0

a = 1; b = 8; c = -72;
Δ = b2-4ac
Δ = 82-4·1·(-72)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{22}}{2*1}=\frac{-8-4\sqrt{22}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{22}}{2*1}=\frac{-8+4\sqrt{22}}{2}
$